Electrical Engineering ⇒ Topic : Magnetic force
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Gaurav
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Magnetic force. It is the force exerted by one magnet on another to attract it or repel it | |
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Mason
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MAGNETIC FORCE Electrostatic forces have been discussed in Chapter, where it was stated that if a charge q is placed in an electric field of intensity E, then the electrostatic force experienced by the charge is Fe = q. E newtons ...........(1) The force Fe acts along E and the charge experiences the force, whether it is atrest or moving. In a similar way, a moving charge q in a magnetic field will experience a magnetic force given by Fm = q(u x B) newtons ............ (2) Here, q is the charge in Coulombs, u is the velocity of the moving charge in m/s, and B is the magnetic flux density in Wb/m2. The direction of the force is given by the cross product (u x B) and will be perpendicular to the plane determined by u and B as shown in Fig. (a). The magnitude of the force Fm is given as Fm = q.u.B sin θ ...............(3) where, θ is the angle between the vectors u and B. The following cases can be visualised: Case (a) When θ = 0 : When the charge q moves along the magnetic field, O becomes zero and the force experienced by the charge also becomes zero. Case (b) When θ = π/2: When θ = π/2, the force is in a direction normal to the direction of the magnetic field and the force experienced by the charge is maximum. The maximum force is given as Fm =q.u.B newtons and this acts normal to the velocity vector. The acceleration of q is given by FIGURE (a) Illustrating Fm = q. (U x B) where, m is the mass of the charged particle. The acceleration acts along Fm. Since the acceleration and the velocity vectors are mutually perpendicular, the component of a along u is zero. Therefore, there is no change in the initial velocity of the charged particle when it is in the magnetic field, but its direction changes. This implies that there is no change in the kinetic energy of the particle in the original direction of motion. But in an electric field, the charge is accelerated in the direction of the field E and the velocity of the particle increases continuously. The particle acquires kinetic energy from the electric field | |
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