Electrical Engineering ⇒ Topic : Special Cases of ParallelPlate Capacitor

Maninder
 
Special Cases of ParallelPlate Capacitor We have seen that capacitance of a capacitor depends upon plate area, thickness of dielectric and value of relative permittivity of the dielectric. We consider two cases by way of illustration (1) Fig. (a) shows that dielectric thickness is d but plate area is divided into two parts; area A_{1} having air as the dielectric and area A_{2} having dielectric of relative permittivity ε_{r}. The arrangement is equivalent to two capacitors in parallel. Their capacitances are
The total capacitance C of this parallel plate capacitor is C = C_{1} + C_{2} _{} _{ (A) (B)} _{ FIGURE } (2) Fig. 6.10 shows that plate area is divided into two parts ; area A1 has dielectric (air) of thickness d and area A2 has a dielectric (80 of thickness t and the remaining thickness is occupied by air The anangement is equivalent to two capacitors connected in parallel. Their capacitances are
The total capacitance C of this parallel plate capacitor is C = C_{1} + C_{2}  
 
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