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Why induction motor draws heavy current at starting?
Induction motor is similar to transformer. If you look at its equivalent diagram you will see that impedance is equal t?
Z( Starting impedance)= R/S - jX
Slip is maximum at the start and gradually it decreases so impedance in running condition increases and hence current drawn by motor starts to decreases.
Z( Running impedance) = R/S' -JX
Z( Starting impedance) < Z( running impedance)
Z( Starting impedance)= R/S - jX
Slip is maximum at the start and gradually it decreases so impedance in running condition increases and hence current drawn by motor starts to decreases.
Z( Running impedance) = R/S' -JX
Z( Starting impedance) < Z( running impedance)