Electrical Engineering ⇒ Topic : Electric Field Intensity due to a Point Charge at Rest
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April
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Electric Field Intensity due to a Point Charge at Rest Consider a charge q placed in free space. Let Δq be the test charge placed at a distance d from q. The elementary force acting on Δq due to q is ΔF, which is given as ΔF = q Δq/4πε0 r2 acting along the line joining q and Δq. Therefore i.e. The electric field intensity at a point where q is placed is defined as the force per unit charge and therefore Electric field intensity (E) is a vector since F is a vector, and is expressed as Newton/Coulomb (N/C). This suggests that if E is known at any point in the medium, the electrostatic force can be computed, since F =E x q .............(4) Therefore, electric field intensity due to a point charge q which is at a distance r from the charge is given as and acts in a direction away from q. If the charge q is negative, the direction of E is reversed and it acts in the direction of the charge | |
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