Electrical Engineering ⇒ Topic : Calculations of Power Factor Correction

Sunita
 
Calculations of Power Factor Correction From Figure 1 (a), the inductive load (RL) originally takes current I from the source and its power factor is cos Φ_{1} i.e., I lags behind the voltage V by an angle Φ_{1} (Figure 1 (b)). Let a capacitor C be connected in parallel with RL load. So, its current l_{c }is leading in nature and it will partly cancel the reactive component of I and the current drawn by the source will be I' where I' < I and the power factor of the circuit becomes cos Φ_{2}, where cos Φ_{2} > cos Φ_{1}. From Figure 1 (d)
FIGURE (1) From Figure (2), the reactive power supplied by the capacitor is FIGURE (2) The desired result can be obtained if the kVA supplied by the p.f. correction equipment is known.  
 
!! OOPS Login [Click here] is required for more results / answer